Hydraulic Motor Displacement Calculator

Hydraulic Motor Displacement Formula:

\[ Disp_{motor} = \frac{Q \times 2\pi}{RPM \times \eta} \]

Motor Displacement (Disp_motor):

Unit Converter ▲

Unit Converter ▼

From:	To:

1. What is Hydraulic Motor Displacement?

Hydraulic motor displacement refers to the volume of fluid required to rotate the motor's output shaft through one complete revolution. It is a key parameter in hydraulic system design and determines the motor's torque output and speed characteristics.

2. How Does the Calculator Work?

The calculator uses the hydraulic motor displacement formula:

\[ Disp_{motor} = \frac{Q \times 2\pi}{RPM \times \eta} \]

Where:

\( Q \) — Flow rate (L/min)
\( RPM \) — Rotational speed (revolutions per minute)
\( \eta \) — Efficiency (unitless, typically between 0-1)
\( 2\pi \) — Mathematical constant (approximately 6.2832)

Explanation: The formula calculates the theoretical displacement volume required per revolution based on the input flow rate, motor speed, and system efficiency.

3. Importance of Motor Displacement Calculation

Details: Accurate motor displacement calculation is crucial for proper hydraulic system design, ensuring optimal performance, efficiency, and preventing component damage due to improper sizing.

4. Using the Calculator

Tips: Enter flow rate in L/min, rotational speed in RPM, and efficiency as a decimal value between 0 and 1. All values must be positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: What is the typical efficiency range for hydraulic motors?
A: Hydraulic motor efficiency typically ranges from 0.85 to 0.95 for modern high-efficiency motors, though this can vary based on motor type and operating conditions.

Q2: How does displacement affect motor performance?
A: Larger displacement motors produce higher torque at lower speeds, while smaller displacement motors operate at higher speeds with lower torque output.

Q3: Can this formula be used for all types of hydraulic motors?
A: This formula provides a theoretical calculation that applies to most positive displacement hydraulic motors, though actual performance may vary based on specific motor design.

Q4: Why is the 2π constant included in the formula?
A: The 2π constant converts the flow rate from volume per minute to volume per revolution, accounting for the circular nature of rotational motion.

Q5: What units are used for the displacement result?
A: The result is provided in cm³/rev (cubic centimeters per revolution), which is the standard unit for hydraulic motor displacement.